Question

Find the zeros of the polynomial function and state the multiplicity of each. f(x) = 3(x + 9)2(x - 9)3

Answer 1

In this quadratic function the 0's are where x = -9 and 9. They both have multiplicity of 1. This is just how many times hey occor in the polynomial. If grouped they will have an exponent.

Answer 2

Answer: The zeroes are -9,-9, 9, 9, 9.

Explanation:

Since we have given that

`f(x)=3(x+9)^2(x-9)^3`

We need to find the zeroes and the multiplicity.

As we can see that

(x+9) has multiplicity of 2.

(x-9) has multiplicity of 3.

so, the zeroes of the polynomial function is given by

`x+9=0\\\\x=-9\\\\x-9=0\\\\x=9`

Hence, the zeroes are -9,-9, 9, 9, 9.