Question

We can show that ∆ABC is congruent to ∆A′B′C′ by a translation of unit(s) and a across the -axis.

Answer 1

We can show that ∆ABC is congruent to ∆A′B′C′ by a translation of 2unit(s) right and a reflection across the X-axis.

Answer 2

We can show that ΔABC is congruent to ΔA'B'C' by a translation of 2 unit(s) Left and a Reflection across the x axis.

Explanation:

The given triangles ABC and A'B'C' are congruent.

If we take a point A of ΔABC and A' of ΔA'B'C' then we get the coordinates of A as (8,8) and A' (6,-8)

Therefore, shifting of A to A' = (8_6) = 2 unit on x axis and no translation in y-coordinates.

So translation of 2 units left has occurred.

In addition to this ΔABC is reflected by x-axis to form A'B'C'.