(−14x^3y^3+4x^5 y6)÷(2x^4y^5)

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asked Oct 14, 2019 197k views

1 Answer

Belens · Answer 1 · 2019-10-18T05:19:47+0000

( - 14x^3)(y^3) + 4x^5y^6)/(2x^4y^5)

= 4x^5y^6 - 14x^3y^3/2x^4y^5

= 4x^2y^3 - 14/2xy^2

= 2x^2y^3 - 7/xy^2

Answer: 2x^2y^3 - 7/xy^2

Hope that helps!!!!

(−14x^3y^3+4x^5 y6)÷(2x^4y^5)

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