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Find three consecutive even integers such that the sum of twice the first and three times the second is 52 more than the third.

Find three consecutive even integers such that the sum of twice the first and three times the second is 52 more than the third.
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7 votes
Find three consecutive even integers such that the sum of twice the first and three times the second is 52 more than the third.

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User Rydell
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1 Answer

5 votes
The three integers such as the sum of twice the first and three times second is 52 which is now equal to 62.
answered
User Stu Mackellar
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7.6k points
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