Question

Brian is solving the equation x^2-3/4x=5. What value must be added to both sides of the equation to make the left side a perfect-square trinomial?

Answer 1

The answer is A
Why?
x^2 -3/4 x =5
(x - 3/8)^2 = 5 + 9/64

Answer 2

Given equation is :

`x^(2) -(3x)/(4) =5`

Step 1: half of coefficient of x

`(-3)/(4) *(1)/(2) = (-3)/(8)`

Squaring this we get

`((-3)/(8) )^(2) = (9)/(64)`

step 2:

Adding
`(9)/(64)` to both sides

`x^(2) -(3x)/(4) +(9)/(64) = 5 +(9)/(64)`