Question

(09.10)

Find the area of the sector of the circle with central angle of 225° and radius of 5 cm. Round to the nearest hundredth.

Answer 1

`\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\ ------\\ r=5\\ \theta =225 \end{cases}\implies A=\cfrac{(225)(\pi )(5)}{360}\implies A=\cfrac{25\pi }{8}`