A ship is moving with a constant acceleration of 36km/hr2 in a fixed direction speeds up from 12 km/hr to 18km/hr. Find the distance traveled by the ship in this period

Question

asked Apr 5, 2019 140k views

1 Answer

Rosdi Kasim · Answer 1 · 2019-04-10T21:01:11+0000

v square - u square = 2as. here s=distance
here v squared= 18 squared=324
u squared=12 squared=144
324-144=2×36×s
180=72s
hence distance=2.5