Question

Anyone know how to do this ?

Answer 1

`\log_b\sqrt{(57)/(74)}=\log_b\left((57)/(74)\right)^(1)/(2)=(1)/(2)\log_b(57)/(74)=(1)/(2)(\log_b57-\log_b74)\\\\=(1)/(2)\log_b57-(1)/(2)\log_b74\\-----------------------------\\Used:\\\\√(a)=a^(1)/(2)\\\\\log_ab^n=n\log_ab\\\\\log_a(m)/(n)=\log_am-\log_an\\\\a(b-c)=ab-ac`