Question

What volume of a 0.580-m solution of cacl2 contains 1.28 g solute?

Answer 1

To find the volume of a 0.580 M solution of CaCl2 that contains 1.28 g solute, we can use the formula: moles = mass / molar mass. The volume is 20 mL.

Step-by-step explanation:

To find the volume of a 0.580 M solution of CaCl2 that contains 1.28 g solute, we can use the formula:

moles = mass / molar mass

First, we need to calculate the number of moles of CaCl2:

moles = 1.28 g / 110.98 g/mol = 0.0115 mol

Next, we can use the formula:

moles = concentration x volume

to find the volume:

0.0115 mol = 0.580 M x volume

volume = 0.0115 mol / 0.580 M = 0.020 L = 20 mL

Answer 2

Answer : 19.9 mL

Explanation : We have the moles of Calcium chloride and the weight of it as 1.28 g,

Here, molarity has to be related with the volume so, 0.580 M = 0.580 mol/L

so now in 1.28 g there will be : 1.28 X (1 g / 111 mol of calcium chloride) = 0.01153 mol

Now, we can find out the volume from this;

0.01153 mol X (1 L / 0.580 mol) X (1000 mL / 1 L) = 19.9 mL

Hence, the volume will be 19.9 mL