Question

If x=2y=4z, express

1. x+4y+z and 2. 2x+3y+2z in terms of z, and find the value of the expression when z=2.

Answer 1

`x = 4z`


`2y = 4z`

Dividing both sides by two,


`y = 2z`

OK, part 1.


`x+4y+z = 4z + 4(2z) +z = 13z`

When
`z=2` then
`x+4y+z =13(2)=26`

Part 2.


`2x+3y+2z= 2(4z) +3(2z) + 2z = 16z`

When
`z=2` then
`2x+3y+2z=16(2)=32`