Question

Evaluate the summation of 3 times negative 2 to the n minus 1 power, from n equals 1 to 5..

−93
−33
33
93

Answer 1

he is correct, the answer is 33

Answer 2

For n = [1,2,3,4,5] you can evaluate the series as follows:


`3( -2)^(1-1) +3( -2)^(2-1) +3( -2)^(3-1) +3( -2)^(4-1)+3( -2)^(5-1)`
= 3 + (-6) + (12) + (-24) + (48)
= 63 - 30
= 33