Question

The coordinates of trapezoid EFGH are E(4, 6), F(2, 3), G(4, 2), and H(8, 4). The image of EFGH under dilation is E'F'G'H'.

If the coordinates of vertex G' are (2, 1), what are the coordinates of vertex H'?

Answer 1

G'(2, 1) = (1/2)·G(4, 2)

The dilation factor is 1/2. Applying that to H, we get
(1/2)·H(8, 4) = H'(4, 2)