Question

Can i get some help real quick?

Answer 1

we know h(x) is -(1/4)x-1 only for those values x ≠ 1.

h(-3) simply means x = -3, and since -3 ≠ 1, then we use the subfunction -(1/4)x-1


`\bf h(-3)\implies -\cfrac{1}{4}(-3)-1\implies -\cfrac{-3}{4}-1\implies \cfrac{3}{4}-1\implies \boxed{-\cfrac{1}{4}}`

h(4) simply means x = 4, and since 4 ≠ 1, then we use the subfunction -(1/4)x-1


`\bf h(4)\implies -\cfrac{1}{4}(4)-1\implies -\cfrac{4}{4}-1\implies -1-1\implies \boxed{-2}`

h(1) simply means x = 1, wait just a second!! we know that when x = 1, h(x) is using the constant of -3.


`\bf h(1)=\boxed{-3}`

Answer 2

If you can download this app called photo math then hold it up to the question it will show you the answer