How do yousolve for x 3x^2 + 14x = -8

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asked Jul 6, 2019 172k views

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Gxvigo · Answer 1 · 2019-07-13T04:09:45+0000

Step 1: Subtract -8 from both sides.
3x^2+14x-(-8)=-8(-8)

Step 2: Factor left side of the equation
(3x+2)(x+4)=0

Step 3: Set factors equal to 0.
3x+2=0 or x+4=0

x=-2/3 or x=-4

Hopefully this helps you out.

How do yousolve for x 3x^2 + 14x = -8

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