Question

If 0.0225 g of a gas dissolves in 2.73 l of water at 758 torr, at what pressure would you be able to dissolve 0.134 g in the same amount of water?

Answer 1

Answer: 4,510

Step-by-step explanation:

Answer 2

Answer : 4514.311 torr

Explanation : Using henry's law in simplified version;


`(C_(1))/(P_(1)) = (C_(2))/(P_(2))`

where
`C_(1)` is the concentration of gas in first case which is 0.0225 g
and

`C_(2)` is the concentration of gas in second case which is 0.134 g

the concentration of water is ignored as it remains the same in both the cases.

And,
`P_(1)` is 758 torr and
`P_(2)` needs to be found.

on substituting the values we get,
`P_(2)` = (0.134 X 758) / 0.0225 = 4514.311 torr