Question

Find the limit of the function by using direct substitution. limit as x approaches zero of quantity x squared minus five.

Answer 1

Simply plug in x = 0

f(x) = x^2 - 5
f(0) = 0^2 - 5
f(0) = -5

Answer: -5

Answer 2

The value of limit is -5

Explanation:

Given:
`\lim_(x\rightarrow 0)x^2-5`

We need to find limit by direct substitution.

"quantity x squared minus five" : x²-5

We will put x=0 into function.

`L=\lim_(x\rightarrow 0)x^2-5`

`L=0^2-5`

`L=0-5`

`L=-5`

Hence, The value of limit is -5