Question

How many non-real solutions are in x^2+5=0

Answer 1

If we solve for for x-squared, we would have
`x^(2) =-5` and then
`x=+/- √(-5)`. The solutions are
`x= √(-5)` and
`x=- √(-5)`. Both solutions are non-real because you can't take the square root of a negative number without involving the imaginary "i".