Question

An alloy of tin is 15% tin and weights 20 pounds. A second allow is 10% tin. How many pounds of the second alloy must be added to the first to get a 12% mixture?

30 lb

40 lb

60 lb

Answer 1

Let x represent the amount to be added. The total amount of tin will be
15%·20 + 10%·x = 12%·(20+x)
(15%-12%)·20 = (12%-10%)·x
3%·20/2% = x
30 = x

30 pounds of 10% tin must be added to get a 12% mixture.