Question

URGENT! Please and Thanks :)

If triangle ABC has A = 113, side a = 200, and side b = 134, then which of the following is true?


A. angle B=38.08 degrees 
B. angle B=141.92 degrees
C. angle B=38.08 degrees or 141.92 degrees
D. no solution

Answer 1

angle B=38.08 degrees

Explanation:

ape.x

Answer 2

For this case we will define the following:
A, B: are the values of the triangle angles
a, b: are the values of the lengths of the sides opposite the angles A, B.
We then have to use the law of the sine:

`(sinB)/(b) = (sinA)/(a)`
Clearing the angle B we have:

`sinB = (sinA)/(a)*b`

`B = arcsin((sinA)/(a)*b)`
Substituting values we have:

`B = arcsin((sin113)/(200)*134)`

`B = 38.08`
Answer:
the following is true:
A. angle B=38.08 degrees