Question

What is the exact value of x in the exponential equation 3.2 + e6x = 54.2?

Answer 1

To solve this problem you must apply the proccedure shown below;
1. You have the following exponential equation given in the problem above:
3.2+e^(6x)=54.2
2. You must solve for e, as following:
e^(6x)=54.2-3-2
e^(6x)=51
3. By applying ln, you obtain:
ln(e)^(6x)=ln(51)
6x=ln(51)
x=ln(51)/6
x=0.65
Therefore, the answer is: x=0.65