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If f(x) = 1/9x - 2, what is f^-1(x)? a. f^-1(x) = 9x + 18B. f^-1(x) = 1/9x + 2C. f^-1(x) = 9x + 2D. f^-1(x) = 2x + 1/9

If f(x) = 1/9x - 2, what is f^-1(x)? a. f^-1(x) = 9x + 18B. f^-1(x) = 1/9x + 2C. f^-1(x) = 9x + 2D. f^-1(x) = 2x + 1/9
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If f(x) = 1/9x - 2, what is f^-1(x)?

a. f^-1(x) = 9x + 18B. f^-1(x) = 1/9x + 2C. f^-1(x) = 9x + 2D. f^-1(x) = 2x + 1/9

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User Epameinondas
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2 Answers

5 votes

Answer:

a is correct on edge

Explanation:

answered
User Derkoe
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7.8k points
7 votes
f(x) = 1/9x - 2 and your job is to find the inverse function.

For simplicity let f(x)=y

y=1/9x-2 and you need to solve this for x
y+2=1/9x
9y+18=x

Thus F(x)^-1=9x+18
answered
User Randomsolutions
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