Question

Of 120 visitors to an amusement park, 84 stayed for at least 3 hours, 76 spent at least $20, and 60 stayed for at least 3 hours and spent at least $20. What is the probability that a randomly selected visitor stayed for at least 3 hours and spent less than $20?

Answer 1

24 of the 120 visitors stayed at least 3 hours and spent less than $20. The probability that such a visitor is chosen at random is 24/120 = 1/5.