asked 223k views
4 votes
How many moles of nitrogen are contained in 18.65 l at stp?

asked
User Raaghu
by
8.4k points

2 Answers

4 votes

Answer: 0.832

Step-by-step explanation:

answered
User Adamup
by
8.4k points
2 votes
We can use the ideal gas law equation to find the number of moles of nitrogen at STP
PV = nRT
Where
P - standard pressure - 1 atm
V - 18.65 L
n - number of moles
R - universal gas constant - 0.0821 L.atm/mol.K
T - standard temperature -273 K
Substituting the values in the equation
1 atm x 18.65 L = n x 0.0821 L.atm/mol.K x 273 K
n = 0.832 mol
There are 0.832 mol of Nitrogen gas in the container
answered
User Fola
by
7.9k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.