asked 197k views
4 votes
If ABCD ≅ QRST, m∠A = x - 10, and m∠Q = 2x - 30, what is m∠A?

asked
User Duncanp
by
8.7k points

2 Answers

2 votes
If ABCD ≅ QRST, then m∠A = m∠Q,
so
x-10 = 2x - 30
2x-x=30-10
x=20

m∠A = x - 10 =20-10 = 10
m∠A = 10⁰

answered
User Steven Combs
by
8.6k points
2 votes

Answer:


m\angle A = 10^\circ

Explanation:

We are given the following information in the question:


ABCD \cong QRST\\m\angle A = x -10\\m\angle Q = 2x-30

Since,quadrilateral ABCD is congruent to the quadrilateral QRST, then by the property of congruency, we can write,


m\angle A = m\angle Q

Equating the value of the two angles, we get,


m\angle A = m\angle Q\\x - 10 = 2x - 30\\2x - x = 30-10\\x = 20

Putting the value of x to obtain measure of angle A.


m\angle A = x -10 = 20-10\\m\angle A = 10^\circ

Thus, the measure of angle A is 10 degrees.

answered
User Shmil The Cat
by
8.7k points
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