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a pool in the shape of rectangle has a perimeter of 80 feet. The pool is 8 Feet less wide than its long. Find the length and width of the pool

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Hello!

To solve this, lets put it into a system of equations where w=width and L=length.
2w+2L=80
L-8=w

To solve, we see that w=L-8. We can substitute this in the first equation to find L and then w.

2(L-8)+2L=80
2L-16+2L=80
4L-16+80
4L-16=80
4L=96
L=24

Now that we know L=24, we can find w. 24-8=16. Now we know that L=24 and w=16.

Lets check our answer. In our original system of equations, we have 48+32=80, which is true, and 24-8=16. Also, the perimeter must equal 80. 16+16+24+24=80.

As our final answer, the width of the pool is 16 feet, and the length is 24 feet.

Hope this helps!

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User Relasta
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