Question

(03.01 lc) the leg of a right triangle is 2 units and the hypotenuse is 3 units. What is the length, in units of the other leg of the triangle

Answer 1

hypotenuse^2 = leg1^2 + leg2^2
3^2 = 2^2 + leg2^2
leg2^2 = 3^2 -2^2
leg2^2 =9 -4
leg2^2 = 5
leg2 = square root (5)

Answer 2

For this case, the first thing we should do is use the Pythagorean theorem.
We have then:

`c ^ 2 = a ^ 2 + b ^ 2`
Where,
a, b: sides of the rectangle triangle
c: hypotenuse
Substituting values we have:

`3 ^ 2 = 2 ^ 2 + b ^ 2`
Clearing b we have:

`b ^ 2 = 3 ^ 2 - 2 ^ 2`

`b = √(3^2 - 2^2)`

`b = √(9-4)`

`b = √(5)`
Answer:
The length, in units of the other leg of the triangle is:

`b = √(5)`