check the picture below.
so the pyramid is really just 4 triangular faces with a
base of 5 and a height of 8, and a
5x5 square at the bottom, now, if we just get the area of all 4 triangles and the square, sum them up, that's the area of the pyramid in feet.
![\bf \stackrel{\textit{4 triangles}}{4\left[ \cfrac{1}{2}(5)(8) \right]}~~+~~\stackrel{\textit{square}}{5\cdot 5}\implies 80+25\implies 105~feet^2 \\\\\\ \stackrel{\textit{there are }9ft^2\textit{ in }1yd^2}{105\underline{ft^2}\cdot \cfrac{yd^2}{9\underline{ft^2}}\implies \cfrac{105}{9}yd^2\implies \cfrac{35}{3}yd^2\implies 11(2)/(3)~yd^2}](https://img.qammunity.org/2019/formulas/mathematics/high-school/8p5uy2vz97c83xkrkgbdq6hiqyp7dq1pif.png)