Question

What volume would 0.435 moles of hydrogen gas, h2, occupy at stp?

Answer 1

The conversion factor for volume at STP is
`\frac {1mol}{22.4L}` or
`\frac {22.4L}{1mol}`. Since we want volume, we would use
`\frac {22.4L}{1mol}`. We conclude with the following calculations:


`0.435mol H_(2) * \frac {22.4LH_(2)}{1molH_(2)} = 9.744L`

The answer is 9.744L H2

Answer 2

Answer: The volume occupied by 0.435 moles of
`H_2` will be 9.7 Liters.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number
`6.023* 10^(23)` of particles.

Thus if 1 mole of
`H_2` occupies 22.4 L at STP

0.435 moles of
`H_2` occupies=
`(22.4)/(1)* 0.435=9.8L` L at STP

The volume occupied by 0.435 moles of
`H_2` will be 9.7 Liters.