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Let ​ f(x)=x^2+10x+37 ​ the minimum value is -5,12 what is the vertex form?

Let ​ f(x)=x^2+10x+37 ​ the minimum value is -5,12 what is the vertex form?
asked 37.3k views
3 votes
Let ​ f(x)=x^2+10x+37 ​
the minimum value is -5,12
what is the vertex form?

asked
User Shahid Ahmad
by
8.0k points

1 Answer

1 vote
Hi,(-5,12) being the vertex,
the vertex form is y=(x+5)²+12

answered
User Pierre Prinetti
by
8.2k points
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