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Find the dimensions of a rectangle whose width is 10 miles less than its length and whose area is 75 square miles. L= ? W= ?
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Find the dimensions of a rectangle whose width is 10 miles less than its length and whose area is 75 square miles. L= ? W= ?
asked
Sep 14, 2019
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Find the dimensions of a rectangle whose width is 10 miles less than its length and whose area is 75 square miles.
L= ?
W= ?
Mathematics
high-school
RussellStewart
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length = L
width =( L-10)
Area of rectangle =L*(L-10)
L*(L-10) = 75
L²-10L-75 = 0 -75= (-15)*5, -10= - 15+ 5
(L-15)(L+5)=0
L=15,L=-5
We can take only positive root,
so L=15 mi.
W=L-10=15-10=5
W=5 mi
Answer:
L=15 mi
,
W=5mi.
Briantist
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Sep 19, 2019
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Briantist
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