Question

Tyler slides across his kitchen floor. the coefficient of kinetic friction between his socks and the tile is 0.3. if his mass is 67 kg, what is the force of friction acting on him?

Answer 1

The force of friction acting on Tyler is given by:

`F=\mu N` (1)
where
`\mu` is the coefficient of friction, and N is the normal force exerted by the floor on Tyler. However, the normal force is equal to Tyler's weight:

`N=mg`
where m is Tyler's mass and g is the gravitational acceleration. Therefore, the frictional force (1) becomes

`F=\mu mg=(0.3 )(67 kg)(9.81 m/s^2)=197 N`