Question

A baseball player hits a ball at an angle of 52 degrees and at a height of 4.8 ft. if the ball's initial velocity after being hit is 150 and if no one catches the ball when will it hit the ground?

Answer 1

C. 7.43

Step-by-step explanation:

Answer 2

The vertical velocity of the ball is:
`(150(ft)/(s))(sin52) = 118.2(ft)/(s)`. Since gravity acts at
`-32(ft)/(s^2)`, this means that the time of flight up to the maximum height (at which vertical velocity is 0) would be:


`(0 - 118.2)=(-32)t \\ t = 3.69 s`
This maximum height is:

`4.8 + 118.2t + 0.5(-32)t^2 \\ = 4.8 + 118.2(3.69) - 16(3.69)^2 \\ = 223.1 ft`
Then the time for it to fall down will be:


`0.5(-32)(t_(2))^2=-223.1 \\ t_2 = 3.73s`
The total time will be 3.69 + 3.73 = 7.42 seconds.