Question

Use the zero product property to find the solutions to the equation

2x2 – x – 15 = x(x + 1).
A. x= -5 or x=3
B. x= -7/2 or x=2
C. x= -3 or x=5
D. x= -5/2 or x=3

Answer 1

2x2 – x – 15 = x(x + 1)
x2 - 2x - 15 = 0
(x - 5)(x + 3) = 0

x = -3 , 5

Its C

Answer 2

Explanation:

We are given an equation , so we first need to simplify the equation

lets distribute the x on parenthesis first

`2x^2 -x- 15 = x^2 + x.`

Now bring all terms to the left so we get

`2x^2-x-15-x^2-x=x^2+x-x^2-x`

`x^2-2x-15=0`

Now since all terms are in one side , so we now factor the equation

`(x-5)(x+3)=0`

Now apply the zero product property to get

x-5=0 or x+3=0

x=5 or x=-3

solution x=-3 or x=5

C