Question

what is the force on a hockey puck when shot with a stick? the pucks mass is 0.155 kg and it leaves the stick at 40 m/s. the contact time between the puck and the stick is 1.1 millisecond

Answer 1

According to the Newton's second law of motion:

Force = mass × acceleration

Acceleration = change in speed ÷ time

Therefore,

Force =mass × (change in speed/time)

Acceleration = 40 m/s ÷ 1.1 millisecond

Acceleration = 40 m/s ÷ 0.001 seconds

Acceleration = 40,000 m/s²

Hence,

F = m × a

F = 0.155 kg × 40,000 m/s²

F = 4,600 kg·m/s² (Newtons)