Question

Which equation can you use to evaluate log61,296? a6 = 1,296 6a = 1,296 6a = 1,296

Answer 1

`6^a = 1296`

Explanation:

Using the logarithmic properties:

`\log_b x = a`

⇒
`x = b^a`

Given the equation:

`\log_6 1296 = a`

Apply the logarithmic properties we have;

`1296 = 6^a`

or

`6^a = 1296`

Therefore,
`6^a = 1296` equation can you use to evaluate
`\log_6 1296 = a`