To solve this problem you must apply the proccedure shown below:
1. You have the following quadratic equation given in the exercise above:
2x²−6x+1=0
2. The quadratic equation is:
x=[-b±√(b²-4ac)]/2a
Where:
a=2
b=-6
c=1
3. When you substitute these values into the quadratic equation, you obtain:
x=3/2-√(7)/2
x=3/2+√(7)/2