Question

Given that segments AE = 4 in, DE = 12 in, and EF = 8 in.

What is the measure of segment EB?

A. 6 in.
B. 16 in.
C. 24 in.
D. 4 in.

Answer 1

we know that
When two chords intersect each other inside a circle, the products of their segments are equal (Intersecting Chord Theorem)
so
AE*EB=DE*EF-----> EB=DE*EF/AE
AE=4 in
DE=12 in
EF=8 in
EB=?
EB=DE*EF/AE
EB=12*8/4-----> EB=24 in