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Solve sin θ = 0.95 for -90º ≤ θ ≤ 90º

Solve sin θ = 0.95 for -90º ≤ θ ≤ 90º
asked 52.2k views
1 vote
Solve sin θ = 0.95 for -90º ≤ θ ≤ 90º

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User Haseoh
by
7.4k points

1 Answer

1 vote
sin θ = 0.95
Solving for θ:
θ = sin^(-1) 0.95
θ = 71.80512766°
θ = 71.8°
The sine is positive in the interval 0° to 180°

Answer: θ = 71.8°
answered
User Dmitry Meshkov
by
8.3k points
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