Question

Can someone solve this for me? Thanks.

Answer 1

use this formula

`log_(5)(10x + 5) - log_(5)(x - 7) = \\ log_(5)( (10x + 5)/(x - 7) )`

after thet you have


`log_(5)( (10x + 5)/(x - 7) ) = 2`
open this up


`(10x + 5)/(x - 7) = {5}^(2)`
and from now you sould be fine!