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5 votes
A circle whose center is at (5, -3) and which passes through the point (7, -8) has a radius equal to

1 Answer

5 votes
The distance from the center to any point on the circle is the radius.
Use the distance formula to find the radius:
d =
\sqrt{(x_(2) - x_(1))^(2) + ( y_(2) - y_(1))^(2) }
=
\sqrt{(5 - 7)^(2) + (-3 + 8})^(2)}
=
\sqrt{(-2)^(2) + (5})^(2)}
=
√((4 + 25))
=
√(29)

Answer: the radius of the circle is
√(29)

answered
User Nakres
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