Question

A cash register contains $10bills and $20bilk with a total value amount of $340. If there are 23 bills total, then how many of each does the register contain?

Answer 1

14 dollars and 8 cents

Answer 2

We are given that the cash register contains $10 and $20 bills.

Let us say there are x number of $10 bills and y number of $20 bills.

So there are total 23 bills.

`x+y=23`..............(1)

`x=23-y`.........(2)

We are also given that the total value of bills is $340 .

So that gives us the second equation,

`10x+20y=340`.........(3)

Plugging the value of x from equation (2) in (3),

`10(23-y)+20y=340`

`(230-10y)+20y=340`

`10y=110`

y=11

Plugging this value of y back in equation (2),

x=23-11= 12

Answer: So there are 12 bills of $10 and 11 bills of $20.