asked 82.1k views
1 vote
The angle of elevation to the top of a 10-story skyscraper is measured to be 3 degrees from a point on the ground 2,000 feet from the building. What is the height of the building to the nearest hundredth foot?

A. 104.82 feet
B. 285.09 feet
C. 66.58 feet
D. 104.67 feet

asked
User Phyllie
by
8.4k points

2 Answers

1 vote

Answer:

104.82 ft

Explanation:

A P E X

answered
User Wit Wikky
by
7.9k points
6 votes

Answer: A. 104.82 feet

Explanation:

You can observe in the figure a right triangle, where the height of the building is "x".

You need to use the identity:


tan\alpha=(opposite)/(adjacent)

You can identify in the figure that:


opposite=x\\adjacent=2,000\\\alpha=3\°

Then, you can substitute these values into
tan\alpha=(opposite)/(adjacent):


tan(3\°)=(x)/(2,000)

Solve for x:


x=(2,000)(tan(3\°)\\x=104.815

Therefore, the height of the building to the nearest hundredth foot is:

104.82 feet

The angle of elevation to the top of a 10-story skyscraper is measured to be 3 degrees-example-1
answered
User Linghua Zhang
by
9.0k points

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