How many solutions does a triangle with side lengths a = 6, a equals 110 degree , and b = 10 have?

Question

asked Apr 1, 2019 51.3k views

2 Answers

Ventero · Answer 1 · 2019-04-05T23:56:43+0000

Answer:

No solution

Explanation:

We are given some dimension of triangle.

a=6

∠A=110°

b=10

Using sine law, we will find rest part of the triangle.

$(a)/(\sin A)=(b)/(\sin B)=(c)/(\sin C)$

Substitute the value into formula

$(6)/(\sin 110^\circ)=(10)/(\sin B)=(c)/(\sin C)$

$(6)/(\sin 110^\circ)=(10)/(\sin B)$

$\sin B=1.56$

$\angle B=\sin^(-1)(1.56)$

$\angle B=\text{Not Possible}$

Because value of sine can't be more than 1.

No solution for triangle. No such triangle form.

Hence, The number of triangle for given info is zero