Question

15 Points!

A building has a ramp to its front doors to accommodate the handicapped. If the distance from the building to the end of the ramp is 20 feet and the height from the ground to the front doors is 6 feet, how long is the ramp? (Round to the nearest tenth.)

A) 3.7 ft

B) 5.1 ft

C) 19.1 ft

D) 20.9 ft

Answer 1

Look at the picture.
Use Pythagorean theorem:

`r^2=6^2+20^2\\\\r^2=36+400\\\\r^2=436\to r=√(4\cdot109)\to r=2√(109)ft.\\\\r\approx20.88\approx20.9ft.`

Answer: D) 20.9 ft

Answer 2

Using the Pythagorean Theorem we can solve this:

20^2 + 6^2 = X^2

400 + 36 = x^2

436 = x^2

x = SQRT(436)

x = 20.9 feet long