asked 177k views
5 votes
Which function has a range of (−90°, 90°)?

A) f(x) = sin−1(x)
B) f(x) = cos−1(x)
C) f(x) = tan−1(x)
D) f(x) = sec−1(x)

A is the answer.

asked
User Estel
by
7.6k points

1 Answer

0 votes
Yes you are right because only sin⁻¹(x) is Bijective in the given range.
Option A is correct
answered
User Honk
by
7.4k points
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