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What is the volume of a box that will hold 567 cubes with 1/3 inch sides

What is the volume of a box that will hold 567 cubes with 1/3 inch sides
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What is the volume of a box that will hold 567 cubes with 1/3 inch sides

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User Hugom
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2 Answers

4 votes
567*(1/3in)3= 567/27in3= 21in3
answered
User Karakfa
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4 votes
That volume is ...
567*(1/3 in)³ = 567/27 in³ = 21 in³
answered
User Pravin Satav
by
7.7k points
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