Question

Cylinder A has radius r and height h. Cylinder B has radius 4r and height 4h. How many times greater is the surface area of Cylinder B than the surface area of Cylinder A?

Answer 1

Surface area of cylinder A =2πr²+2πrh
Surface area of cylinder B =2π(4r)²+2π(4r)(4h) =16*(2πr²) +16*(2πrh)=
=16(2πr²+2πrh) =16(Surface area of cylinder A)
Surface area of cylinder B=16(Surface area of cylinder A).
So
the surface area of Cylinder B is 16 times greater than the surface area of Cylinder A.