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What method would you choose to solve the equation? 4x^2-48=0

What method would you choose to solve the equation? 4x^2-48=0
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3 votes
What method would you choose to solve the equation? 4x^2-48=0

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User Chiffa
by
8.5k points

1 Answer

3 votes
I'd definitely factor 4x^2-48 first. Factors are (4)(x^2-12).

This factors further: (4)* (x-2sqrt(3) ) * (x+2sqrt(3) )
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User LeBird
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7.4k points
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