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Use the Law of Sines to find side "b" of the triangle.

PLease dont answer if you dont know... Use the Law of Sines to find side "b&quot-example-1
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User Giker
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Using the law of sins:

side a / sin (angle A) = side b / sin(Angle B)

Side a is opposite angle A, so from the picture we know side a = 50, angle A is 58 degrees and angle B is 48 degrees.

replace those values in the formula we get:

50 / sin(58) = b/ sin(48)

so now we can cross multiply the 2 fractions to get:

50 * sin(48) = b*sin(58)

to get b by itself, divide both sides by sin(58) to get:

b = (50*sin(48)) / sin(58)

b = 43.82

You may need to round the answer as needed.

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User Flaashing
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