Question

Compute the resistance in ohms of a silver block 10 cm long and 0.10 cm2 in cross-sectional area. ( = 1.63 x 10-6 ohm-cm)

Answer 1

1.6 x 10^-4 Ω

Step-by-step explanation:

Answer 2

The resistance of the silver block is given by

`R= (\rho L)/(A)`
where

`\rho=1.63 \cdot 10^(-6) \Omega \cdot cm` is the silver resistivity

`L=10 cm` is the length of the block

`A=0.10 cm^2` is the cross-sectional area of the block

If we plug the data into the equation, we find the resistance of the silver block:

`R= ((1.63 \cdot 10^(-6) \Omega \cdot cm)(10 cm))/(0.10 cm^2)=1.63 \cdot 10^(-4) \Omega`